Thursday, August 26, 2010
Yogurts and the Quantum World
Today, while coming back from the bank, I saw an advertisement of DANONE. Here in India! India is fast becoming a market to expand into.
Well, what a weak link! But I had to mention this. Why exactly it caused me such an excitement when I saw the ad, I can't exactly express. Maybe my country and its people being courted by foreign companies to sell their product? Pride? Or folly that we have to depend on them, still? I wish I knew!
Saturday, August 21, 2010
The Spending Spree in India
There is this travel company called Make My Trip, a pretty well known company in India. I had used this to book some air tickets previously. But, suddenly, a month ago they suddenly offered me a package--for which I had to a pay a service charge of about 7000, and in return they gave me several discount vouchers. They did explain all the terms and conditions--or as much of them as they thought would not put me off in accepting the offer. I was a bit sceptical and so were some of the people I consulted with. But it seemed an interesting thing to experiment with. So I have accepted the offer. The entire package gives you a lot of discounts, but it also necessiates that you spend a lot more than you planned to! I knew all this, but the real challenge to me is how to get the most by spending the least. Lets see how it goes--I have about an year.
But this is indeed what goes on all the time--everywhere---the entire credit system based on the Credit and Debit cards promises you more benefits the more you use them. The more you spend. The more debt you incur.
No longer a scary thought; but a reality to deal with!
Thursday, August 19, 2010
Saturday, July 17, 2010
I was kept wondering. I don't know what happened next, since I think I woke up at that point. If you want to know what happened next, you could try going to sleep after watching the movie, "Race to the witch mountain", and maybe you'll get the same dream I had, or a much more interesting one. Anyway, that's one of the reasons I have trouble in getting up once I fall asleep. So many dreams, so many stories. I yet have to upload my photos and/or tell you about the trip to Lattice and Extreme QCD.
Sunday, May 30, 2010
A tryst with VISA
I am going to travel to Italy and Germany for some conferences and both organizers have graciously provided me with all possible documents to help me get my VISA. But of course, the problem with the Italian consulate was that the person sitting with the phone (who was unfortunately an Indian) thought it was too much to listen to what I had to say--all he could happily say was---Go the the VFS and get rid of us. Okay, I decided, that is probably the best instead of wasting my time. But then it turned out that the great VFS, whose job is to provide information on what type of VISA to provide drew a complete bank look at my covering letter. "Sorry sir",---they very politely told me,"we have to send your application to the Consulate to decide on the type of VISA"--etc etc. You cannot imagine the feelings I had after I had travelled to that place wasting so much of my time and money and in the unbearable heat. So what do I do? Nothing, but meekly go back again the next day! And what do they do then---accept the form as it is--and now all because the Consulate has told them. What a big fallacy! And why, because some stupid Indian guy at the Consulate had thought it was beneath his status to talk to the ordinary public. Maybe, I should write a proper letter of complaint to the Consul General.
But anyway---sometimes I wonder whats the point--in today's world, it is the first of the many VISA related frustrations that I am probably going to have! :( !
Monday, May 24, 2010
24+15
Thursday, May 20, 2010
Links and more
But this is only the beginning of the things that I have to finish before the month is over. Yes, let me go back...
Monday, May 17, 2010
Hunting for treasure
Well anyway, although the treasure hunt was important for me, since I was playing this time with a lot of friends, we lost by about a minute. It might be of interest that the winning team took about 40 minutes to decide that the sequence 3 14 15 ... has anything at all to do with the fabled $\pi$. But it was fun and it was tiring.
Back, I have a lot of catch up to do despite the fact that I worked pretty hard yesterday. The SU3 prog is coming up from the SU2 one; and am trying to think the correct tuning for the multilevel process. I was told that the optimum no of sublattice averaging in the latter case might go up to thousands but I didn't appreciate it properly until I saw the Koma et al paper that does the same. That does bring up the question where are we going to get so much time? Another thing that was pointed out, was that could we do any calculation in the strong coupling limit of the theory? Well, it is time I tried to understand the Laine et al paper much more seriously.
Sunday, May 09, 2010
And yes, got to see a lot of wonderful sights from the plane. The sight of Bombay, as the plane was taking off----that of the Worli sea link was particularly wonderful. The roads were tubelights of light! So was Calcutta while getting down. It seemed so "cute"! While coming back, the most remarkable were that of the Western Ghats: you can make out where the ranges start, grow taller, some parts of the plateau sandwiched in between the mountains, and finally the mountains giving way to the narrow valley and finally the sea----mesmerising. You could see deep gorges when the river is in the mountain and ox-bow lakes as it is moving on a flat land: geography should be taught on the air like this!
Working hard on the Diffusion coefficient. Need to see how much the multilevel improves over the standard result.
Friday, April 23, 2010
No physics for so many days. No physics posts till now. Very frustrating, indeed!
Tuesday, April 20, 2010
Monday, April 19, 2010
Saturday, December 16, 2006
Electric Dipole Moment
The Energy of a system of charges is defined as:
ε=∫ρΦ dV
where ρ is the charge density and Φ the potential both functions of coordinates.Choosing a particular origin and expanding the potential in a Taylor series about the origin:
ε=∫ρ{Φ(r0)+xi&parti&Phi(r0)+½ xixj&parti&partj&Phi(r0)+...}
ε=∫ρΦ(r0)+diEi+dijEiEj+...
where di is the Electric Dipole Moment and dij is the Induced Dipole Moment and E the electric field.
For discrete charges the dipole moment is
d=&Sigmairiei
where i denotes the sum over the charges.
EDM for a system
Let P is the Parity operator.If P is conserved then the energy eigenstates are also
parity eigenstates.Under a parity transformation
&lang m|P+PdP+P|m &rang =-&lang m|d|m &rang .
So the dipole moment must vanish.A non-vanishing dipole moment signals violation of parity.
Let us consider non-degenerate energy eigenstates characterised by only by its angular momentum operator J.
Under the action of time reversal,
T d T-1 =d
T J T-1 =-J
implying the EDM has to vanish.
So, the presense of an electric dipole moment would violate both time reversal and parity.
However, a system possessing non-degenerate eigenstates which are parity eigenstates as well can have a non vanishing dipole moment.This is because the energy shift is quadratic in &Delta2 where &Delta is &lang+|zEz|- &rang and therefore quadratic in E.So it is an induced dipole moment and doesnt imply the violation of time reversal.
When the system is in a degenerate state ( for example the ground state of a water molecule), the energy shift can be linear in E, but then it does not imply violation of time reversal invariance.This is usually called the permanent dipole moment.
Monday, November 20, 2006
Projection Operators
pijψ(...,i,...,j,...)= ψ(...,j,...,i,...) ( 1)
In general, pij2= e2iφ
The order of the permutation group of order N is N!.Further, if the hilbert space of each single particle state is d,dimension of the total hilbert space formed is dN.The particles are assumed to be indistinguishable.
Completely Symmetric & Completely Antisymmetric States and Projection Operators:
Notation: |i1,...,iα,...,iN> is a multiparticle state which means that particle no α is in a state denoted by |iα>.If the |i>'s form a complete orthonormal system in the space of N-particle system,the completely symmetric and completely antisymmetric basis states is defined by:
S±|i1,...,iα,...,iN>=(1/√ N!) Σp(±)pp|i1,...,iα,...,iN> (2)
By definition,it is clear that S± are 1-dimensional subspaces.This we can also prove by writing down the projection operators onto these states.The trace of the projection perators is equal to the dimensionality of the hilbert space onto which they project as can be seen from the example of a three dimensional vector.From this elementary consideration, the following properties of the projection operators can be formulated:
1.Tr P < D,where D is the dimensionality of the hilbert space.
2.Tr P is always integral.
3.If Tr P =0 then it projects on to the null space.
4.If PiPj=&deltaij and Tr Pi=1, then i can lie between 1 and D.
5.Iff 1 ≤ i ≤ D, then Σ i Pi=I
Now, let us give some theorems and their proofs.
Theorem 1: The trace of a projection operator is equal to the dimension of the Hilbert space over which it projects.
Proof:Let the basis of an d dimensional Hilbert space be denoted as {|i 〉 }.The projection operator Pr which projects over a r dimensional subspace can then be written as Σ k=1 r |k 〉 〈 k|.Then Tr P= Σl=1 D 〈 l| P |l 〉 = Σl=1 D 〈l Σk=1 r |k 〉 〈 k|l 〉 =Σk=1 r Σl=1 D 〈 l|k 〉〈 k|l 〉=Σk=1 r1 = r, since
〈 k|l 〉=δkl.
Theorem 2:The Projection Operator on to the completely symmetric and the completely antisymmetric states are given by
P±=(1/√ N!)S± (2)
Proof:From our definition of the S± operators we know that there can only be a single symmetric or anti-symmetric state.So let us write
P+=c+ S+.We need to find c+ such that P+2=P+
Now, P+2|i1,...,iα,...,iN&rang =(1/N!)c+2&Sigmaqpqp|i1,...,iα,...,iN&rang
=(1/N!)c+2&Sigmaphh|i1,...,iα,...,iN&rang
=c+2&Sigmahh|i1,...,iα,...,iN&rang
(since if pq=h, then p=hq(-1) and has N! distinct elements.)
=c+2(√ N!)S+|i1,...,iα,...,iN&rang
=c+(√ N!)P+|i1,...,iα,...,iN&rang
which implies c+=(1/√ N!)
Thus:
P±=(1/N!) &Sigma p(±)pp|i1,...,iα,...,iN&rang
Theorem 3:Tr P±=1
Proof: We shall prove this theorem only for the case of P+.The other one involves more complicated algebra, but gives the same result.
Tr P+=&Sigma{|i 〉 } &lang i1,...,iα,...,iN|(1/N!)&Sigmapp|i1,...,iα,...,iN&rang
Only p=1 gives non zero contribution and there are N! such identities are generated due to the sum on p and hence we have the result Tr P+=1
Saturday, October 14, 2006
noethers theorem
2.next, we also considered the cases where the end points vary and noted that such a variation of end points causes the lagrangian to remain otherwise unchanged.this variation causes a variation of the coordiantes at the boundary, but along the trajectory.the limits of integration change.for the action to remain unchanged, the change of lagrangian due to this must equal the change of lagrangian due to the coordinate variation.a short calcualtion then yielded the conservation of energy.
3.we also saw that the alpha_k 's form a lie algebra
4.we derived the energy momentum tensor of the field.we noted that the tensor was not unique and so certain tensors(anti-symmetric in the last two indices) can be added to it to symmetrize it.
5.we derived its form for the classical electromagnetic field, checked that the tensor was symmetric and traceless.
6.it was also noted that this tensor cannot always be diagonalised; since under such a transformation the metric (which is not an identity metric, it is a minkowski metric) must also be preserved.
Thursday, October 12, 2006
further points of discussion
in general represented by rotations of phase space.
2.the second pair of maxwell equations
3. we saw that quantum mechanics is a field theory in some sense.this is because we can always obtain the klein-gordon equation (which describes quantum mechanics) from an action which can be said to describe a classical field theory in 0+1 dimension.
4.some discussions on path integrals
interesting points of fields in lower dimensions
in 1+1 dim, the field tensor is a 2X2 matrix with only one independent component.this component is the 01 component:which is one space and one time.so this is an electric field.note that E is a polar vector and so is the 01 component; hence the electric field is a scalar in 1+1 dimension.
all components exhausted, there is no B in 1+1 dimension!!
this also follows from Biot-savart law; the force on a current due to another current acts in a direction prependicular ot the line joining them, which is not possible in 1 space.
now lets come to 2 +1 dim.the electric field has 2 components.
what about the magnetic field ?
recall biot-savart law.force is given as a cross pdt, it has the structure of Fj=εjkvkB so it turns out that it is a scalar.also since F and v are polar vectors,B must ont change sign under parity and hence it is a true vector.
Bianchi identity: suppose u have an antisymmetric object and u have an operator that acts linearly on the tensor , then the sum of all cyclic permutations of the tensor add up to zero.
Fij=DjAi – DiAj (1)
define tijk=DkFij (2)
then the bianchi identity is
Tijk=tijk+tjki+tkij=0 (3)
as can be shown by substituting 1 & 2 in 3.
Next,using the anti-symmetric properties of Tijk in 3 we see that only 4 non-trivial equations result.knowing that this involves no source terms, we suspect these to be the source free maxwell equations.there are the right number of them!so the bianchi identity are the source free maxwell equations
why do you need a four-vector potential to characterize the field in the action formulation?well,this is because you have E from a scalar potential and B from a vector potential.
note that the convention E= -div (phi) comes from the convention that a positive charge moves in the direction of lower field.
the sturcture of the bianchi identity, ie, of some linear operator acting on an antisymetric structure is the same as for maxwell equations.
ED#
Sunday, October 08, 2006
Into Electrodynamics
Using the principle of least action,the lagrangian is determined to be
L=-mc^2*sqrt(1-v^2/c^2)
Then we go ahead to find the expressions for momentum and energy in the case of a free particle.the euler-lagrange equations of motion(ELEOM) give us the condition that the four-velocity must be a constant.
LL makes the comment that the energy in relativistic mechanics is always positive and proportional to the mass, unlike in class mech where it can be either positive or negative.That would be because in class mech u do have the potential energy of interaction of a system of particles.but to do so in rel. mech. one has to explicitly include the momentum and energy of the field produced by the interacting particles.
A short review was also made of the angular momentum tensor, its antisymmetric nature.
Next, we come to the section where the field is viewed as an physical entity that mediates interactions between particles, since relativity allows only contact interaction.A particle imparts the information about its motion to the field surrounding it, which then propagate it far away.Also, since relativiy disallows the concept of rigid bodies, the so called elementary particles must be pointlike.
the next sections are more mathematical.in them we use the four-vector A to characterise the field, obtain the lagrangian, the generalised momentum,the hamiltonian.Then we proceed further to obtain the ELEOM and define the elecric and magnetic fields.interestingly, we see that the work done on the particle is only by the electric field E, since the magnetic field B is always perpendicular to the velocity v.
Equations of motion in classical mechanics are time reversal invariant; the same thing is true in electrodynamics under the transformation t-> -t; E -> E ; B -> -B which in turn implies phi -> phi; A -> -A; phi and A being the components of the four vector A.
then i studied gauge invariance and solutions for E,B and energy in constant electomagnetic fields.
Friday, October 06, 2006
four vectors
there is one thing i wanted to clarify.A quantity that is a product of a pseudoscalar and a scalar is a pseudoscalar; the product of a pseudoscalar with another pseudoscalar would be a scalar.I can extend the same argument to vectors and tensors; and then i would claim that (levi-civita_iklm)*(levi-civita_prst) is a true tensor.